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Beliebt Rechnen >

(y^{''}+4y^'+20y)^2=0

Lösung

(y^{^{''}} + 4 y^{^{'}} + 20 y)^{2} = 0

Lösung

y = e^{- 2 t} (c_{1} cos (4 t) + c_{2} sin (4 t))

Schritte zur Lösung

(y^{''} (t) + 4 y^{'} (t) + 20 y)^{2} = 0

Solve linear ODE:

y = e^{- 2 t} (c_{1} cos (4 t) + c_{2} sin (4 t))

y = e^{- 2 t} (c_{1} cos (4 t) + c_{2} sin (4 t))

Graph

Beliebte Beispiele

f^{''}(x)+f(x)=0,f(0)=1

f^{^{''}} (x) + f (x) = 0, f (0) = 1

y^{'''}+y^{''}-7y^'+5y=0

y^{^{'''}} + y^{^{''}} - 7 y^{^{'}} + 5 y = 0

linear y^{''}+2y=0,y(0)=1,y^'(0)=1

l in e a r y^{^{''}} + 2 y = 0, y (0) = 1, y^{^{'}} (0) = 1

y^{''''}-y^{'''}+2y^'=0

y^{^{''''}} - y^{^{'''}} + 2 y^{^{'}} = 0

(y^{''}-ay^')=by

(y^{^{''}} - a y^{^{'}}) = b y