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Popular >

y^{''}+4*y=0

Solution

y^{^{''}} + 4 \cdot y = 0

Solution

y = c_{1} cos (2 t) + c_{2} sin (2 t)

Solution steps

y^{''} (t) + 4 \cdot y = 0

Solve linear ODE:

y = c_{1} cos (2 t) + c_{2} sin (2 t)

y = c_{1} cos (2 t) + c_{2} sin (2 t)

Graph

Popular Examples

y^{''}-6y^'-216y=0

y^{^{''}} - 6 y^{^{'}} - 216 y = 0

u^{''}+7\H(t)=0,\H(0)=0,u^'(0)=7

u^{^{''}} + 7 H (t) = 0, H (0) = 0, u^{^{'}} (0) = 7

y^{''}+4y^'+13y^'=0

y^{^{''}} + 4 y^{^{'}} + 13 y^{^{'}} = 0

y*α+(d^2y)/(dx^2)=0

y \cdot α + \frac{d ^{2} y}{d x ^{2}} = 0

4y^{''}-4y^'-3y=0,y(0)=1,y^'(0)=1

4 y^{^{''}} - 4 y^{^{'}} - 3 y = 0, y (0) = 1, y^{^{'}} (0) = 1

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+4*y=0 ?
The solution for y^{''}+4*y=0 is y=c_{1}cos(2t)+c_{2}sin(2t)