y^{''}+y=0,y^'(pi/2)=0,y(0)=0

Lösung

y^{^{''}} + y = 0, y^{^{'}} (\frac{π}{2}) = 0, y (0) = 0

y = c_{2} sin (t)

Schritte zur Lösung

y^{''} (t) + y = 0

Solve linear ODE:

y = c_{2} sin (t)

y = c_{2} sin (t)

\frac{d ^{2} y}{d x ^{2}} - 6 \frac{d y}{d x} + 9 y = 0, y (0) = 0

y^{^{''}} - 6 y^{^{'}} + 12 y = 0, y (0) = 0, y^{^{'}} (0) = - 7

y^{^{''}} + 3 y^{^{'}} = 0, y (0) = - 2, y^{^{'}} (0) = - 3

y^{^{''}} + y = 0, y (0) = - 1

y^{^{''}} + 64 y = 0, y (π) = 0, y (0) = 0