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Beliebt Rechnen >

1.5y^{''}+12y^'+24y=0

Lösung

1.5 y^{^{''}} + 12 y^{^{'}} + 24 y = 0

Lösung

y = c_{1} e^{- 4 t} + c_{2} t e^{- 4 t}

Schritte zur Lösung

1.5 y^{''} (t) + 12 y^{'} (t) + 24 y = 0

Solve linear ODE:

y = c_{1} e^{- 4 t} + c_{2} t e^{- 4 t}

y = c_{1} e^{- 4 t} + c_{2} t e^{- 4 t}

Graph

Beliebte Beispiele

y^{''}-7y^'+12y=0,y^0=0,y^'=3

y^{^{''}} - 7 y^{^{'}} + 12 y = 0, y^{0} = 0, y^{^{'}} = 3

49y^{''}+140y^'+136y=0,y(0)=7,y^'(0)=6

49 y^{^{''}} + 140 y^{^{'}} + 136 y = 0, y (0) = 7, y^{^{'}} (0) = 6

y^{''}+16y^'+63y=0,y(0)=9,y^'(0)=-69

y^{^{''}} + 16 y^{^{'}} + 63 y = 0, y (0) = 9, y^{^{'}} (0) = - 69

2 y^{^{''}} + 25 y = 0

y^{''}+0.46y^'+128y=0

y^{^{''}} + 0.46 y^{^{'}} + 128 y = 0