derivative y^{-1}+y^{-2}

Lösung

ableitung von

y^{- 1} + y^{- 2}

- \frac{1}{y ^{2}} - \frac{2}{y ^{3}}

Schritte zur Lösung

\frac{d}{d y} (y^{- 1} + y^{- 2})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (y^{- 1}) + \frac{d}{d y} (y^{- 2})

\frac{d}{d y} (y^{- 1}) = - \frac{1}{y ^{2}}

\frac{d}{d y} (y^{- 2}) = - \frac{2}{y ^{3}}

= - \frac{1}{y ^{2}} - \frac{2}{y ^{3}}

\int_{- 1}^{0} x^{2} - 1 d x

x \to - 9 + lim (\frac{1}{x + 9})

t an g e n t y = 6 x^{2} - x^{3} (1.5)

x \to 0 lim (1 - x^{2})

\int \frac{x}{( 1 + x ) ^{2}} d x