What is the solution for (dy}{dt}= 1/10 ln(\frac{2000)/y)y ?

The solution for (dy}{dt}= 1/10 ln(\frac{2000)/y)y is y=(2000)/(e^{e^{\frac{-t-c_{1)}{10}}}}

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(dy}{dt}= 1/10 ln(\frac{2000)/y)y

\frac{d y}{d t} = \frac{1}{10} ln (\frac{2000}{y}) y

y = \frac{2000}{e ^{e^{\frac{- t - c _{1}}{10}}}}

Solution steps

\frac{d y}{d t} = \frac{1}{10} ln (\frac{2000}{y}) y

Solve separable ODE:

y = \frac{2000}{e ^{e^{\frac{- t - c _{1}}{10}}}}

y = \frac{2000}{e ^{e^{\frac{- t - c _{1}}{10}}}}

\int csc^{2} (1) d x

f (x) = \frac{x ^{3} - 1}{2 x + 3}

(1 + 3 x^{2}) (x - x^{2})

x \to 2 lim (x^{2} - 3 x + 5)

What is the solution for (dy}{dt}= 1/10 ln(\frac{2000)/y)y ?
The solution for (dy}{dt}= 1/10 ln(\frac{2000)/y)y is y=(2000)/(e^{e^{\frac{-t-c_{1)}{10}}}}