derivative g(x)= 2/(x^3)-1/(x^2)

解

導関数

g (x) = \frac{2}{x ^{3}} - \frac{1}{x ^{2}}

- \frac{6}{x ^{4}} + \frac{2}{x ^{3}}

解答ステップ

\frac{d}{d x} (\frac{2}{x ^{3}} - \frac{1}{x ^{2}})

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{2}{x ^{3}}) - \frac{d}{d x} (\frac{1}{x ^{2}})

\frac{d}{d x} (\frac{2}{x ^{3}}) = - \frac{6}{x ^{4}}

\frac{d}{d x} (\frac{1}{x ^{2}}) = - \frac{2}{x ^{3}}

= - \frac{6}{x ^{4}} - (- \frac{2}{x ^{3}})

簡素化

= - \frac{6}{x ^{4}} + \frac{2}{x ^{3}}