derivative of (-9x-1/(-6x+2))

Lösung

\frac{d}{d x} (\frac{- 9 x - 1}{- 6 x + 2})

- \frac{6}{( 3 x - 1 ) ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{- 9 x - 1}{- 6 x + 2})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( - 9 x - 1 ) ( - 6 x + 2 ) - \frac{d}{d x} ( - 6 x + 2 ) ( - 9 x - 1 )}{( - 6 x + 2 ) ^{2}}

\frac{d}{d x} (- 9 x - 1) = - 9

\frac{d}{d x} (- 6 x + 2) = - 6

= \frac{( - 9 ) ( - 6 x + 2 ) - ( - 6 ) ( - 9 x - 1 )}{( - 6 x + 2 ) ^{2}}

Vereinfache

\frac{( - 9 ) ( - 6 x + 2 ) - ( - 6 ) ( - 9 x - 1 )}{( - 6 x + 2 ) ^{2}} : - \frac{6}{( 3 x - 1 ) ^{2}}

= - \frac{6}{( 3 x - 1 ) ^{2}}

in v erse l a pl a ce \frac{1}{( s - 1 ) ^{3}}

\int \frac{1 - x}{1 - x} d x

\int cosh^{2} (x - 1) sinh (x - 1) d x

\frac{d}{d x} (ln (x^{l n (x)}))

d er i v a t i v e f (x) = x^{7} cos (x)