derivative (h^2-2h+5)/8

解答

导数

\frac{h ^{2} - 2 h + 5}{8}

\frac{h - 1}{4}

求解步骤

\frac{d}{d h} (\frac{h ^{2} - 2 h + 5}{8})

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{8} \frac{d}{d h} (h^{2} - 2 h + 5)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{8} (\frac{d}{d h} (h^{2}) - \frac{d}{d h} (2 h) + \frac{d}{d h} (5))

\frac{d}{d h} (h^{2}) = 2 h

\frac{d}{d h} (2 h) = 2

\frac{d}{d h} (5) = 0

= \frac{1}{8} (2 h - 2 + 0)

化简

\frac{1}{8} (2 h - 2 + 0) : \frac{h - 1}{4}

= \frac{h - 1}{4}

d er i v a t i v e 3 x^{\frac{1}{4}} (x^{3} - 5)

x \to \infty lim (\frac{x - cos ( x )}{x})

\frac{d y}{d x} = x e^{6 x - 5 y}

\frac{d}{d x} (\frac{2 x - x ^{2}}{x})

2 y^{^{''}} + 8 y^{^{'}} + 80 y = 40 cos (8 t)