integral of (7/(t^2)-5t^5)

Lösung

\int (\frac{7}{t ^{2}} - 5 t^{5}) d t

- \frac{7}{t} - \frac{5 t ^{6}}{6} + C

Schritte zur Lösung

\int \frac{7}{t ^{2}} - 5 t^{5} d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{7}{t ^{2}} d t - \int 5 t^{5} d t

\int \frac{7}{t ^{2}} d t = - \frac{7}{t}

\int 5 t^{5} d t = \frac{5 t ^{6}}{6}

= - \frac{7}{t} - \frac{5 t ^{6}}{6}

Füge eine Konstante zur Lösung hinzu

= - \frac{7}{t} - \frac{5 t ^{6}}{6} + C

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