(dy)/(dx)=(x-3)e^{-2y},y(3)=ln(3)

Lösung

\frac{d y}{d x} = (x - 3) e^{- 2 y}, y (3) = ln (3)

y = \frac{ln ( x ^{2} - 6 x + 18 )}{2}

Schritte zur Lösung

\frac{d y}{d x} = (x - 3) e^{- 2 y}

Solve separable ODE:

y = \frac{ln ( x ^{2} - 6 x + 18 )}{2}

y = \frac{ln ( x ^{2} - 6 x + 18 )}{2}

d er i v a t i v e y = lo g_{2} (lo g_{2} (x))

x \to 1 lim (- \frac{x ^{2}}{2} + 2 x + 4)

(1 - x y) d x + (x y - x^{2}) d y = 0

\int tan^{2} (x) x d x

\int_{3}^{11} x d x