y^{''}+y=cos(2x)

Lösung

y^{^{''}} + y = cos (2 x)

y = c_{1} cos (x) + c_{2} sin (x) - \frac{1}{3} cos (2 x)

Schritte zur Lösung

y^{''} (x) + y = cos (2 x)

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) - \frac{1}{3} cos (2 x)

y = c_{1} cos (x) + c_{2} sin (x) - \frac{1}{3} cos (2 x)

3 y^{^{''}} - 4 y^{^{'}} - 4 y = 0, y (0) = - 7, y^{^{'}} (0) = - 8

\int (e^{x} + x) d x

\frac{d}{d x} (lo g_{10} (lo g_{10} (x)))

\int_{0}^{\frac{π}{2}} sin (2 x) d x

l a pl a ce t r an s f or m cos (2 t)