What is the derivative of x^3-3x^2+2x ?

The derivative of x^3-3x^2+2x is 3x^2-6x+2

What is the first derivative of x^3-3x^2+2x ?

The first derivative of x^3-3x^2+2x is 3x^2-6x+2

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\frac{d}{d x} (x^{3} - 3 x^{2} + 2 x)

3 x^{2} - 6 x + 2

Solution steps

\frac{d}{d x} (x^{3} - 3 x^{2} + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (2 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

= 3 x^{2} - 6 x + 2

l a pl a ce t r an s f or m e^{- 2 t} sin (3 t)

\int x csc^{2} (x) d x

d er i v a t i v e x^{4} cos (7 x - 5)

d er i v a t i v e 2 a y

y^{^{'}} + 3 y = 2 e^{- x}

What is the derivative of x^3-3x^2+2x ?
The derivative of x^3-3x^2+2x is 3x^2-6x+2
What is the first derivative of x^3-3x^2+2x ?
The first derivative of x^3-3x^2+2x is 3x^2-6x+2