What is the tangent of x^3+y^3=9xy,(4,2) ?

The tangent of x^3+y^3=9xy,(4,2) is y= 5/4 x-3

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tangent of x^3+y^3=9xy,(4,2)

tangent of

x^{3} + y^{3} = 9 x y, (4, 2)

y = \frac{5}{4} x - 3

Solution steps

Find the slope of

x^{3} + y^{3} = 9 x y : \frac{d y}{d x} = \frac{3 y - x ^{2}}{y ^{2} - 3 x}

Compute the slope of

x^{3} + y^{3} = 9 x y

(4, 2) : m = \frac{5}{4}

Find the line with slope m=

\frac{5}{4}

and passing through

(4, 2) : y = \frac{5}{4} x - 3

y = \frac{5}{4} x - 3

x \to - 1 lim (- 4 x^{9} - 2 x^{6} - x^{3})

\frac{d}{d x} (x + ln x^{2} - 4 x + 3)

\int \frac{1}{1 + x} d x

\frac{\partial}{\partial x} (x x^{2} + y^{2})

What is the tangent of x^3+y^3=9xy,(4,2) ?
The tangent of x^3+y^3=9xy,(4,2) is y= 5/4 x-3