(\partial)/(\partial y)(4x^2+y^2)

Lösung

\frac{\partial}{\partial y} (4 x^{2} + y^{2})

2 y

Schritte zur Lösung

\frac{\partial}{\partial y} (4 x^{2} + y^{2})

Behandle

x

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (4 x^{2}) + \frac{\partial}{\partial y} (y^{2})

\frac{\partial}{\partial y} (4 x^{2}) = 0

\frac{\partial}{\partial y} (y^{2}) = 2 y

= 0 + 2 y

Vereinfache

= 2 y

\frac{\partial}{\partial y} (8 - 2 x^{2} + y^{2})

d er i v a t i v e f (x) = x^{2} (x^{2} + 1)

\frac{\partial}{\partial y} (x e^{- x^{2} - y^{2}})

\int_{0}^{4} x 16 - x^{2} d x

\int \frac{1 - t}{t} d t