What is the derivative of 4x^2+6x ?

The derivative of 4x^2+6x is 8x+6

What is the first derivative of 4x^2+6x ?

The first derivative of 4x^2+6x is 8x+6

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\frac{d}{d x} (4 x^{2} + 6 x)

8 x + 6

Solution steps

\frac{d}{d x} (4 x^{2} + 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (6 x)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (6 x) = 6

= 8 x + 6

\frac{\partial}{\partial s} (s^{6} + t^{6})

\frac{df}{d x} + 2 f = f x^{3}

n = 0 \sum \infty (\frac{1}{3})^{n}

a re a 2 x^{2} + 3, x, (- 1, 2)

\int_{- 2}^{2} π (4 - x^{2}) d x

What is the derivative of 4x^2+6x ?
The derivative of 4x^2+6x is 8x+6
What is the first derivative of 4x^2+6x ?
The first derivative of 4x^2+6x is 8x+6