derivative 0.03x^2-4x+3x^{0.8}-5000

解答

导数

0.03 x^{2} - 4 x + 3 x^{0.8} - 5000

0.06 x + \frac{2.4}{x ^{0.2}} - 4

求解步骤

\frac{d}{d x} (0.03 x^{2} - 4 x + 3 x^{0.8} - 5000)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (0.03 x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (3 x^{0.8}) - \frac{d}{d x} (5000)

\frac{d}{d x} (0.03 x^{2}) = 0.06 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (3 x^{0.8}) = \frac{2.4}{x ^{0.2}}

\frac{d}{d x} (5000) = 0

= 0.06 x - 4 + \frac{2.4}{x ^{0.2}} - 0

化简

= 0.06 x + \frac{2.4}{x ^{0.2}} - 4

\int - \frac{t}{1 + t ^{2}} d t

t an g e n t f (x) = 14 cos (x), at x = 7

y^{^{'}} + ln (x) = \frac{y}{x}

\int_{0}^{1} 1 + (- \frac{1}{x})^{2} d x

in v erse l a pl a ce \frac{( 6 )}{s ^{2} + 5 s + 6}