derivative f(x)=x^3-2x^2+x+1

Lösung

ableitung von

f (x) = x^{3} - 2 x^{2} + x + 1

3 x^{2} - 4 x + 1

Schritte zur Lösung

\frac{d}{d x} (x^{3} - 2 x^{2} + x + 1)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (2 x^{2}) + \frac{d x}{d x} + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 3 x^{2} - 4 x + 1 + 0

Vereinfache

= 3 x^{2} - 4 x + 1

\int_{- 2}^{- 1} \frac{1}{( x - 1 ) ^{3}} d x

a re a 7 x + 12, 0, 10

in v erse l a pl a ce \frac{1}{s ^{3} ( s + 2 )}

\frac{\partial}{\partial x} (x^{2} y + y^{2} z + z^{2} x)

x^{- 2} y^{- 5} d x + x^{- 3} y^{- 4} d y = 0