y^'sqrt(y-x^2y)=-xy

Lösung

y^{^{'}} y - x^{2} y = - x y

y = - \frac{1}{4} x^{2} + \frac{1}{4} + c_{1} - x^{2} + 1 + c_{1}^{2}

Schritte zur Lösung

y^{'} (x) y - x^{2} y = - x y

Solve Bernoulli ODE:

y = - \frac{1}{4} x^{2} + \frac{1}{4} + c_{1} - x^{2} + 1 + c_{1}^{2}

y = - \frac{1}{4} x^{2} + \frac{1}{4} + c_{1} - x^{2} + 1 + c_{1}^{2}

\int tan^{5} (x) sec^{3} (x) d x

\frac{\partial}{\partial x} (x^{2})

\int x^{4} - 8 x^{3} + 26 x^{2} - 40 x + 25 d x

x \to 7 lim (\frac{x - 7}{x - 7})

x \to 0.5 + lim (3 x)