derivative 4e^x+x

Lösung

ableitung von

4 e^{x} + x

4 e^{x} + 1

Schritte zur Lösung

\frac{d}{d x} (4 e^{x} + x)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 e^{x}) + \frac{d x}{d x}

\frac{d}{d x} (4 e^{x}) = 4 e^{x}

\frac{d x}{d x} = 1

= 4 e^{x} + 1

t an g e n t (x + 1) (4 x^{2} - 4 x - 8)

\frac{\partial}{\partial x} (x^{3} y - x y^{3})

t an g e n t f (x) = \frac{4}{x}, at x = 3

x \to 0 lim (x^{2} cos (\frac{2}{x}))

n = 1 \sum \infty \frac{1}{3 ^{n} + n}