derivative f(x)=e^x+x^e

Lösung

ableitung von

f (x) = e^{x} + x^{e}

e^{x} + e x^{e - 1}

Schritte zur Lösung

\frac{d}{d x} (e^{x} + x^{e})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) + \frac{d}{d x} (x^{e})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (x^{e}) = e x^{e - 1}

= e^{x} + e x^{e - 1}

\frac{d}{d x} (sec (8 x))

\int_{0}^{1} e^{x^{3}} d x

t an g e n t f (x) = \frac{- 2 x}{x ^{2} + 1}, (1, - 1)

\frac{\partial}{\partial x} ((13 - x)^{80})

y (1 + x^{2}) y^{^{'}} = x (1 + y^{2})