(\partial)/(\partial y)(3x^2y^2-3)

解

\frac{\partial}{\partial y} (3 x^{2} y^{2} - 3)

6 x^{2} y

解答ステップ

\frac{\partial}{\partial y} (3 x^{2} y^{2} - 3)

x

を定数として扱う

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{2} y^{2}) - \frac{\partial}{\partial y} (3)

\frac{\partial}{\partial y} (3 x^{2} y^{2}) = 6 x^{2} y

\frac{\partial}{\partial y} (3) = 0

= 6 x^{2} y - 0

簡素化

= 6 x^{2} y