y^'=2y-1

Lösung

y^{^{'}} = 2 y - 1

y = \frac{e ^{2 t + c_{1}}}{2} + \frac{1}{2}

Schritte zur Lösung

y^{'} (t) = 2 y - 1

Solve separable ODE:

y = \frac{e ^{2 t + c_{1}}}{2} + \frac{1}{2}

y = \frac{e ^{2 t + c_{1}}}{2} + \frac{1}{2}

\frac{d}{d x} (x^{\frac{4}{3}} (2 - x)^{3})

\int \frac{49 - x ^{2}}{x ^{4}} d x

\frac{d ^{3}}{d x ^{3}} (x^{6} e^{x})

t an g e n t f (x) = \frac{6 x + 5}{x - 1}, at x = 2

t \to 2 lim (\frac{t - 2}{t ^{2} - 4})