What is the solution for y^'-((2x)/(1+x^2))y=0 ?

The solution for y^'-((2x)/(1+x^2))y=0 is y=e^{c_{1}}x^2+e^{c_{1}}

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y^'-((2x)/(1+x^2))y=0

y^{^{'}} - (\frac{2 x}{1 + x ^{2}}) y = 0

y = e^{c_{1}} x^{2} + e^{c_{1}}

Solution steps

y^{'} (x) - (\frac{2 x}{1 + x ^{2}}) y = 0

Solve separable ODE:

y = e^{c_{1}} x^{2} + e^{c_{1}}

y = e^{c_{1}} x^{2} + e^{c_{1}}

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x \to - 3 lim (- f (x))

\int \frac{sin ( x )}{cos ( x ) + ( cos ( x ) ) ^{2}} d x

\int_{- 1}^{1} 5 d x

\int sin^{2} (\frac{x}{2}) cos (\frac{x}{3}) d x

What is the solution for y^'-((2x)/(1+x^2))y=0 ?
The solution for y^'-((2x)/(1+x^2))y=0 is y=e^{c_{1}}x^2+e^{c_{1}}