derivative of sqrt(2x+x^2)

Lösung

\frac{d}{d x} (2 x + x^{2})

\frac{1 + x}{2 x + x ^{2}}

Schritte zur Lösung

\frac{d}{d x} (2 x + x^{2})

Wende die Kettenregel an:

\frac{1}{2 2 x + x ^{2}} \frac{d}{d x} (2 x + x^{2})

= \frac{1}{2 2 x + x ^{2}} \frac{d}{d x} (2 x + x^{2})

\frac{d}{d x} (2 x + x^{2}) = 2 + 2 x

= \frac{1}{2 2 x + x ^{2}} (2 + 2 x)

Vereinfache

\frac{1}{2 2 x + x ^{2}} (2 + 2 x) : \frac{1 + x}{2 x + x ^{2}}

= \frac{1 + x}{2 x + x ^{2}}

\frac{\partial}{\partial y} (x^{4 y})

x \to - \infty lim (\frac{( 5 x ^{2} - 2 )}{x + 3})

x \to 0 lim (\frac{∣ x - 1 ∣ - 1}{x})

x \to 3 lim (4 x^{3} - 5 x^{2} + x - 8)

\int sec^{2} (x) - csc (x) cot (x) d x