y^'=y^3

Lösung

y^{^{'}} = y^{3}

y = - \frac{1}{2 ( t + c _{1} )}, y = - - \frac{1}{2 ( t + c _{1} )}

Schritte zur Lösung

y^{'} (t) = y^{3}

Solve separable ODE:

y = - \frac{1}{2 ( t + c _{1} )}, y = - - \frac{1}{2 ( t + c _{1} )}

y = - \frac{1}{2 ( t + c _{1} )}, y = - - \frac{1}{2 ( t + c _{1} )}

x \to 2 lim (\frac{x ^{3} - 3 x ^{2} + 4}{3 x ^{3} - 18 x ^{2} + 36 x - 24})

\int_{4}^{\infty} 9 e^{- \frac{y}{2}} d y

\frac{\partial}{\partial x} (ln (x y^{4}))

d er i v a t i v e y = 3 x e^{2 x}

d er i v a t i v e f (x) = 5 x^{2} - x^{3}