2y^'+3y=5

Lösung

2 y^{^{'}} + 3 y = 5

y = - \frac{e ^{\frac{- 3 t - c _{1}}{2}}}{3} + \frac{5}{3}

Schritte zur Lösung

2 y^{'} (t) + 3 y = 5

Solve separable ODE:

y = - \frac{e ^{\frac{- 3 t - c _{1}}{2}}}{3} + \frac{5}{3}

y = - \frac{e ^{\frac{- 3 t - c _{1}}{2}}}{3} + \frac{5}{3}

d er i v a t i v e g (t) = \frac{1}{t}

\int_{1}^{\infty} \frac{2}{e ^{x}} d x

\frac{\partial}{\partial x} (6 y^{2} - 6 x^{2})

t an g e n t f (x) = x^{2} + 2, (2, 6)

t an g e n t f (x) = x^{2} - x, at x = 4