(sin(2t))^'

Lösung

(sin (2 t))^{^{'}}

cos (2 t) \cdot 2

Schritte zur Lösung

(sin (2 t))^{'}

Wende die Kettenregel an:

cos (2 t) (2 t)^{'}

= cos (2 t) (2 t)^{'}

(2 t)^{'} = 2

= cos (2 t) \cdot 2

\int_{0}^{π} 5 x^{2} sin (\frac{1}{2} x) d x

x \to 1 lim (9 x + 5)

t^{2} y^{^{''}} + t y^{^{'}} + 4 y = sin (2 ln (t))

\int - 5 tan^{5} (4 x) sec^{6} (4 x) d x

x \to 0 lim (\frac{tan ( 9 x )}{sin ( 4 x )})