What is the limit as x approaches 0-of (sin(2x))/x ?

The limit as x approaches 0-of (sin(2x))/x is 2

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limit as x approaches 0-of (sin(2x))/x

x \to 0 - lim (\frac{sin ( 2 x )}{x})

2

Solution steps

x \to 0 - lim (\frac{sin ( 2 x )}{x})

Apply L'Hopital's Rule

: x \to 0 - lim (\frac{cos ( 2 x ) \cdot 2}{1})

= x \to 0 - lim (\frac{cos ( 2 x ) \cdot 2}{1})

Plug in the value

x = 0

= \frac{cos ( 2 \cdot 0 ) \cdot 2}{1}

Simplify

\frac{cos ( 2 \cdot 0 ) \cdot 2}{1} : 2

= 2

\int \frac{x ^{3} - 3 x ^{2} + 5 x - 3}{x - 1} d x

y = 3 x - x^{2}, y = - 5 x

f (x) = 3 x + 1, at x = 5

\frac{d}{d x} (2 e^{6 x})

What is the limit as x approaches 0-of (sin(2x))/x ?
The limit as x approaches 0-of (sin(2x))/x is 2