斜率 (19,-16),(-7,-15)

解答

斜率

(19, - 16), (- 7, - 15)

m = - \frac{1}{26}

求解步骤

两点之间的斜率: 斜率

= \frac{y _{2} - y _{1}}{x _{2} - x _{1}}

(x_{1}, y_{1}) = (19, - 16), (x_{2}, y_{2}) = (- 7, - 15)

m = \frac{- 15 - ( - 16 )}{- 7 - 19}

整理后得

m = - \frac{1}{26}

x \to 2 lim (x^{3})

d er i v a t i v e 7 x e^{x}

\frac{\partial}{\partial y} (- \frac{y}{( x + 2 ) ^{2}})

\frac{d}{d x} (\frac{x ^{2} + 1}{3 x ^{3} + 4 x})

\int (e^{x}) d x