derivative of sqrt(4-x^2-4y^2)

Lösung

\frac{d}{d x} (4 - x^{2} - 4 y^{2})

- \frac{x + 4 y \frac{d y}{d x}}{- x ^{2} - 4 y ^{2} + 4}

Schritte zur Lösung

\frac{d}{d x} (4 - x^{2} - 4 y^{2})

Wende die Kettenregel an:

\frac{1}{2 4 - x ^{2} - 4 y ^{2}} \frac{d}{d x} (4 - x^{2} - 4 y^{2})

= \frac{1}{2 4 - x ^{2} - 4 y ^{2}} \frac{d}{d x} (4 - x^{2} - 4 y^{2})

\frac{d}{d x} (4 - x^{2} - 4 y^{2}) = - 2 x - 8 y \frac{d y}{d x}

= \frac{1}{2 4 - x ^{2} - 4 y ^{2}} (- 2 x - 8 y \frac{d y}{d x})

Vereinfache

\frac{1}{2 4 - x ^{2} - 4 y ^{2}} (- 2 x - 8 y \frac{d y}{d x}) : - \frac{x + 4 y \frac{d y}{d x}}{- x ^{2} - 4 y ^{2} + 4}

= - \frac{x + 4 y \frac{d y}{d x}}{- x ^{2} - 4 y ^{2} + 4}

\frac{d}{d x} (arctan (cos (x)))

\int_{0}^{4} ∣ 3 t - 8 ∣ d t

d er i v a t i v e f (x) = \frac{4 x ^{2} - x + 3}{x}

\int \frac{e ^{- s t}}{- s} d t

\int (e^{c o s (x)} sin (x)) d x