What is (\partial)/(\partial x)(cos(6x)) ?

The answer to (\partial)/(\partial x)(cos(6x)) is -sin(6x)*6

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(\partial)/(\partial x)(cos(6x))

\frac{\partial}{\partial x} (cos (6 x))

- sin (6 x) \cdot 6

Solution steps

\frac{\partial}{\partial x} (cos (6 x))

Apply the chain rule:

- sin (6 x) \frac{\partial}{\partial x} (6 x)

= - sin (6 x) \frac{\partial}{\partial x} (6 x)

\frac{\partial}{\partial x} (6 x) = 6

= - sin (6 x) \cdot 6

\frac{d}{d x} (x^{3} + 8 x^{2} + 5 x - 50)

\int \frac{1}{2 + 8 x} d x

\int sec (13 w) tan (13 w) d w

\int_{0}^{\frac{π}{4}} tan^{3} (x) d x

(2 y^{2} x + 3 x^{2}) d x + 2 x^{2} y d y = 0

What is (\partial)/(\partial x)(cos(6x)) ?
The answer to (\partial)/(\partial x)(cos(6x)) is -sin(6x)*6