derivative 9x^3+7^x+20

解答

导数

9 x^{3} + 7^{x} + 20

27 x^{2} + ln (7) \cdot 7^{x}

求解步骤

\frac{d}{d x} (9 x^{3} + 7^{x} + 20)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 x^{3}) + \frac{d}{d x} (7^{x}) + \frac{d}{d x} (20)

\frac{d}{d x} (9 x^{3}) = 27 x^{2}

\frac{d}{d x} (7^{x}) = 7^{x} ln (7)

\frac{d}{d x} (20) = 0

= 27 x^{2} + 7^{x} ln (7) + 0

化简

= 27 x^{2} + ln (7) \cdot 7^{x}

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