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tangent y=-4-7x^2,(-4,-16)

解答

切线

y = - 4 - 7 x^{2}, (- 4, - 16)

解答

y = (207 + 56) x + 208 + 807 or y = (56 - 207) x + 208 - 807

求解步骤

(- 4, - 16)

处的切线斜率:

m = \frac{- 7 x ^{2} + 12}{x + 4}

计算

y = - 4 - 7 x^{2}

的斜率:

m = - 14 x

解

- 14 x = \frac{- 7 x ^{2} + 12}{x + 4} : x = - \frac{2 ( 14 + 5 7 )}{7}, x = - \frac{2 ( 14 - 5 7 )}{7}

求出

x = - \frac{2 ( 14 + 5 7 )}{7}

处的切线:

y = (207 + 56) x + 208 + 807

求出

x = - \frac{2 ( 14 - 5 7 )}{7}

处的切线:

y = (56 - 207) x + 208 - 807

y = (207 + 56) x + 208 + 807 or y = (56 - 207) x + 208 - 807

作图

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