(2x-1)dx+(5y+8)dy=0

解

(2 x - 1) d x + (5 y + 8) d y = 0

y = \frac{- 16 + 256 - 20 ( - c _{1} - 2 x + 2 x ^{2} )}{10}, y = \frac{- 16 - 256 - 20 ( - c _{1} - 2 x + 2 x ^{2} )}{10}

解答ステップ

(2 x - 1) d x + (5 y + 8) d y = 0

分離可能 ODE を解く:

y = \frac{- 16 + 256 - 20 ( - c _{1} - 2 x + 2 x ^{2} )}{10}, y = \frac{- 16 - 256 - 20 ( - c _{1} - 2 x + 2 x ^{2} )}{10}

y = \frac{- 16 + 256 - 20 ( - c _{1} - 2 x + 2 x ^{2} )}{10}, y = \frac{- 16 - 256 - 20 ( - c _{1} - 2 x + 2 x ^{2} )}{10}