y^{''}+5y^'=e^{-t}

Lösung

y^{^{''}} + 5 y^{^{'}} = e^{- t}

y = c_{1} + c_{2} e^{- 5 t} - \frac{1}{4} e^{- t}

Schritte zur Lösung

y^{''} (t) + 5 y^{'} (t) = e^{- t}

Solve linear ODE:

y = c_{1} + c_{2} e^{- 5 t} - \frac{1}{4} e^{- t}

y = c_{1} + c_{2} e^{- 5 t} - \frac{1}{4} e^{- t}

y^{^{'}} + y cos (x) = 2 cos (x)

\int \frac{1 - sin ( x )}{x + cos ( x )} d x

x \to + (- 1) lim (x)

\frac{d}{d x} (- \frac{16}{x ^{3}})

h \to 0 lim (\frac{( x - h ) - x}{h})