What is the solution for y^{''}+17y=0 ?

The solution for y^{''}+17y=0 is y=c_{1}cos(sqrt(17)t)+c_{2}sin(sqrt(17)t)

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y^{''}+17y=0

y^{^{''}} + 17 y = 0

y = c_{1} cos (17 t) + c_{2} sin (17 t)

Solution steps

y^{''} (t) + 17 y = 0

Solve linear ODE:

y = c_{1} cos (17 t) + c_{2} sin (17 t)

y = c_{1} cos (17 t) + c_{2} sin (17 t)

(sin (y))^{^{'}}

n or ma l y = \frac{x}{x + 4}, (1, 0.2)

a re a y = \frac{1}{x}, y = x, y = \frac{1}{4} x

\int x \cdot arcsin (x) d x

e x p an d (x^{2} + x^{3})^{4}

What is the solution for y^{''}+17y=0 ?
The solution for y^{''}+17y=0 is y=c_{1}cos(sqrt(17)t)+c_{2}sin(sqrt(17)t)