limit as x approaches 0 of (1-e^{2x})/x

Lösung

x \to 0 lim (\frac{1 - e ^{2 x}}{x})

- 2

Schritte zur Lösung

x \to 0 lim (\frac{1 - e ^{2 x}}{x})

Wende das L'Hopital Theorem an

= x \to 0 lim (\frac{- 2 e ^{2 x}}{1})

Setze den Wert

x = 0

ein

= \frac{- 2 e ^{2 \cdot 0}}{1}

Vereinfache

= - 2

\int_{- \infty}^{8} r e^{\frac{r}{2}} d r

\frac{d}{d t} (sin (π t))

\frac{\partial}{\partial y} (sin^{3} (x^{2} y))

\int_{- 1}^{1} (x^{2} + 1)^{2} d x

d er i v a t i v e y = e^{- \frac{1}{2} x}