What is the derivative of ln(y-x) ?

The derivative of ln(y-x) is (\frac{dy)/(dx)-1}{y-x}

What is the first derivative of ln(y-x) ?

The first derivative of ln(y-x) is (\frac{dy)/(dx)-1}{y-x}

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\frac{d}{d x} (ln (y - x))

\frac{\frac{d y}{d x} - 1}{y - x}

Solution steps

\frac{d}{d x} (ln (y - x))

Apply the chain rule:

\frac{1}{y - x} \frac{d}{d x} (y - x)

= \frac{1}{y - x} \frac{d}{d x} (y - x)

\frac{d}{d x} (y - x) = \frac{d y}{d x} - 1

= \frac{1}{y - x} (\frac{d y}{d x} - 1)

Simplify

\frac{1}{y - x} (\frac{d y}{d x} - 1) : \frac{\frac{d y}{d x} - 1}{y - x}

= \frac{\frac{d y}{d x} - 1}{y - x}

- x^{2} + 8 x - 9, (\frac{1}{2} x) + 1, x = 3, x = 5

\int_{- \infty}^{0} \frac{1}{7 - 5 x} d x

\int x^{2} (1 - x^{3})^{5} d x

\frac{d}{d x} ((x^{3} + x)^{6})

\frac{d}{d x} (x (6^{- 2 x}))

What is the derivative of ln(y-x) ?
The derivative of ln(y-x) is (\frac{dy)/(dx)-1}{y-x}
What is the first derivative of ln(y-x) ?
The first derivative of ln(y-x) is (\frac{dy)/(dx)-1}{y-x}