integral from 3/4 to 1 of 2x

Lösung

\int_{\frac{3}{4}}^{1} 2 x d x

\frac{7}{16}

Dezimale

0.4375

Schritte zur Lösung

\int_{\frac{3}{4}}^{1} 2 x d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{\frac{3}{4}}^{1} x d x

Wende die Potenzregel an

= 2 [\frac{x ^{2}}{2}]_{\frac{3}{4}}^{1}

Berechne die Grenzen:

\frac{7}{32}

= 2 \cdot \frac{7}{32}

Vereinfache

= \frac{7}{16}

\frac{d y}{d x} + y^{9} x + 6 y = 0

y^{^{''}} + 2 y^{^{'}} + y = e - t ln (t)

\frac{\partial}{\partial y} (\frac{( x - y )}{x + y})

\int_{- 1}^{2} (x^{2} - 1) d x

x \to 2 lim (\frac{3}{( x - 2 ) ^{3}})