y^'=y^2,y(0)=2

Lösung

y^{^{'}} = y^{2}, y (0) = 2

y = - \frac{2}{2 t - 1}

Schritte zur Lösung

y^{'} (t) = y^{2}

Solve separable ODE:

y = - \frac{2}{2 t - 1}

y = - \frac{2}{2 t - 1}

\frac{d}{d x} ((x^{2} \cdot 5^{x})^{9})

x \to 0 lim (\frac{7}{x} - \frac{7}{x ^{2} - x})

x y^{^{''}} + 2 y^{^{'}} - 4 = 0

\frac{\partial}{\partial y} (x^{2} y + 3 x y^{4})

\frac{d}{d x} (7 x^{\frac{3}{2}})