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Popular >

y^'=y^2,y(0)=2

Solution

y^{^{'}} = y^{2}, y (0) = 2

Solution

y = - \frac{2}{2 t - 1}

Solution steps

y^{'} (t) = y^{2}

Solve separable ODE:

y = - \frac{2}{2 t - 1}

y = - \frac{2}{2 t - 1}

Popular Examples

derivative of sqrt((x^2*5^x^9))

\frac{d}{d x} ((x^{2} \cdot 5^{x})^{9})

limit as x approaches 0 of 7/x-7/(x^2-x)

x \to 0 lim (\frac{7}{x} - \frac{7}{x ^{2} - x})

xy^{''}+2y^'-4=0

x y^{^{''}} + 2 y^{^{'}} - 4 = 0

x y^{^{'}} + y = 3 x y^{2}

(\partial)/(\partial y)(x^2y+3xy^4)

\frac{\partial}{\partial y} (x^{2} y + 3 x y^{4})

Frequently Asked Questions (FAQ)

What is the solution for y^'=y^2,y(0)=2 ?
The solution for y^'=y^2,y(0)=2 is y=-2/(2t-1)