xy^3dy=dx,y(1)=2

解答

x y^{3} d y = d x, y (1) = 2

y = 4 4 ln (x) + c_{1}, y = - 4 4 ln (x) + c_{1}

求解步骤

x y^{3} d y = d x

求解可分离方程:

y = 4 4 ln (x) + c_{1}, y = - 4 4 ln (x) + c_{1}

y = 4 4 ln (x) + c_{1}, y = - 4 4 ln (x) + c_{1}

\int \frac{x ^{3} - 3 x ^{2} + 2 x - 4}{x - 1} d x

x \to - 3 lim (\frac{9 - x ^{2}}{x + 3})

\frac{\partial}{\partial x} (ln (\frac{x}{1 - x}))

l a pl a ce t r an s f or m t sin (3 t)

\int (x^{10} - 5 x^{2})^{3} (x^{9} - x) d x