integral of x^2-4x+4

Lösung

\int x^{2} - 4 x + 4 d x

\frac{x ^{3}}{3} - 2 x^{2} + 4 x + C

Schritte zur Lösung

\int x^{2} - 4 x + 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int 4 x d x + \int 4 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 4 x d x = 2 x^{2}

\int 4 d x = 4 x

= \frac{x ^{3}}{3} - 2 x^{2} + 4 x

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{3}}{3} - 2 x^{2} + 4 x + C

\frac{d y}{d x} = \frac{cos ( 12 x )}{e ^{12 y}}

\int_{1}^{2} \frac{15}{x ^{3} + 5 x} d x

s im pl i f y xL (x) - x

y^{^{''}} - y^{^{'}} - 6 y = 0, y (0) = 0, y^{^{'}} (0) = 4

x \to 2 lim (- 6)