What is (\partial)/(\partial x)(5xcos(xy)) ?

The answer to (\partial)/(\partial x)(5xcos(xy)) is 5(cos(xy)-xysin(xy))

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(\partial)/(\partial x)(5xcos(xy))

\frac{\partial}{\partial x} (5 x cos (x y))

5 (cos (x y) - x y sin (x y))

Solution steps

\frac{\partial}{\partial x} (5 x cos (x y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{\partial}{\partial x} (x cos (x y))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = cos (x y)

= 5 (\frac{\partial}{\partial x} (x) cos (x y) + \frac{\partial}{\partial x} (cos (x y)) x)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (cos (x y)) = - sin (x y) y

= 5 (1 \cdot cos (x y) + (- sin (x y) y) x)

Simplify

= 5 (cos (x y) - x y sin (x y))

\frac{\partial}{\partial x} (- h k^{2} + k^{4})

x y \frac{d y}{d x} = y^{2} + x 4 x^{2} + y^{2}

\frac{\partial}{\partial x} (\frac{- x}{y})

n = 1 \sum \infty (2 n + 1)!

\int \frac{8}{x ^{3}} d x

What is (\partial)/(\partial x)(5xcos(xy)) ?
The answer to (\partial)/(\partial x)(5xcos(xy)) is 5(cos(xy)-xysin(xy))