What is the tangent of f(x)=6x^2-6x,\at x=0 ?

The tangent of f(x)=6x^2-6x,\at x=0 is y=-6x

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tangent of f(x)=6x^2-6x,\at x=0

tangent of

f (x) = 6 x^{2} - 6 x, at x = 0

y = - 6 x

Solution steps

Find the tangent point:

(0, 0)

Find the slope of

f (x) = 6 x^{2} - 6 x : \frac{df ( x )}{d x} = 12 x - 6

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 6

Find the line with slope m=

- 6

and passing through

(0, 0) : y = - 6 x

y = - 6 x

\frac{d x}{d t} = (x^{2} - 1) t, x (0) = 0

\int sin^{2} (d) x d x

\frac{d}{d x} (12 x^{3} - 12 x^{2})

\int 7 sin^{5} (x) cos^{3} (x) d x

\frac{\partial}{\partial y} (x e^{x^{2} - y})

What is the tangent of f(x)=6x^2-6x,\at x=0 ?
The tangent of f(x)=6x^2-6x,\at x=0 is y=-6x