y^{''}+8y^'+7y=0

Lösung

y^{^{''}} + 8 y^{^{'}} + 7 y = 0

y = c_{1} e^{- t} + c_{2} e^{- 7 t}

Schritte zur Lösung

y^{''} (t) + 8 y^{'} (t) + 7 y = 0

Solve linear ODE:

y = c_{1} e^{- t} + c_{2} e^{- 7 t}

y = c_{1} e^{- t} + c_{2} e^{- 7 t}

\int sin (x) cos (x) 1 - sin^{4} (x) d x

\frac{\partial}{\partial x} ((3 y) \cdot (2 x)^{- 1})

p a r i t y f (x) = sin (tan (2 x))

d er i v a t i v e 2 (2 x^{5} - 3 x + 2)^{8}

\int 3 x y