What is the integral of (((x+1))/(sqrt(x))) ?

The integral of (((x+1))/(sqrt(x))) is 2/3 x^{3/2}+2sqrt(x)+C

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integral of (((x+1))/(sqrt(x)))

\int (\frac{( x + 1 )}{x}) d x

\frac{2}{3} x^{\frac{3}{2}} + 2 x + C

Solution steps

\int \frac{x + 1}{x} d x

Expand

\frac{x + 1}{x} : x + \frac{1}{x}

= \int x + \frac{1}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x d x + \int \frac{1}{x} d x

\int x d x = \frac{2}{3} x^{\frac{3}{2}}

\int \frac{1}{x} d x = 2 x

= \frac{2}{3} x^{\frac{3}{2}} + 2 x

Add a constant to the solution

= \frac{2}{3} x^{\frac{3}{2}} + 2 x + C

\int x^{8} + 2 x^{6} + x^{4} d x

3 t (\frac{d y}{d t}) + y = t^{2}

f (x) = x^{2} + 16

(2 x y + 2 x) d x - (1 + x^{4}) d y = 0

y^{^{'}} + 8 (tan (8 x)) y = 10 cos (8 x)

What is the integral of (((x+1))/(sqrt(x))) ?
The integral of (((x+1))/(sqrt(x))) is 2/3 x^{3/2}+2sqrt(x)+C