(\partial)/(\partial x)(e^{-x^2-2y^2})

解答

\frac{\partial}{\partial x} (e^{- x^{2} - 2 y^{2}})

- 2 e^{- x^{2} - 2 y^{2}} x

求解步骤

\frac{\partial}{\partial x} (e^{- x^{2} - 2 y^{2}})

将

y

视为常数

使用连锁律:

e^{- x^{2} - 2 y^{2}} \frac{\partial}{\partial x} (- x^{2} - 2 y^{2})

= e^{- x^{2} - 2 y^{2}} \frac{\partial}{\partial x} (- x^{2} - 2 y^{2})

\frac{\partial}{\partial x} (- x^{2} - 2 y^{2}) = - 2 x

= e^{- x^{2} - 2 y^{2}} (- 2 x)

化简

= - 2 e^{- x^{2} - 2 y^{2}} x

\int 8 sec (x) (sec (x) - 4 tan (x)) d x

y^{^{''}} + 8 y^{^{'}} + 4 y = t

\frac{\partial}{\partial y} (sin (z))

a re a 4 x + 9, 144 - x, - 9, 144

d er i v a t i v e \frac{2}{x ^{3}} - \frac{8}{x}