(dy)/(dx)=((x^2y^2))/(1+x)

解答

\frac{d y}{d x} = \frac{( x ^{2} y ^{2} )}{1 + x}

y = - \frac{2}{x ^{2} - 2 x + 2 ln ( 1 + x ) - 3 + c _{1}}

求解步骤

\frac{d y}{d x} = \frac{( x ^{2} y ^{2} )}{1 + x}

求解可分离方程:

y = - \frac{2}{x ^{2} - 2 x + 2 ln ( 1 + x ) - 3 + c _{1}}

y = - \frac{2}{x ^{2} - 2 x + 2 ln ( 1 + x ) - 3 + c _{1}}

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