y^'=2x+y,y(0)=7

Lösung

y^{^{'}} = 2 x + y, y (0) = 7

y = - 2 (x + 1) + 9 e^{x}

Schritte zur Lösung

y^{'} (x) = 2 x + y

Solve linear ODE:

y = - 2 (x + 1) + 9 e^{x}

y = - 2 (x + 1) + 9 e^{x}

t a y l or sin (x) (cos (x) - 1) π

\frac{\partial}{\partial x} (x^{2} + 4 y^{2})

x^{2} y^{^{''}} - x y^{^{'}} + y = \frac{1}{x}

\int_{0}^{0.5} 500 x d x

\int_{0}^{16} x e^{- x} d x